0=x^2+14x-392

Solution for 0=x^2+14x-392 equation:

0=x^2+14x-392

We move all terms to the left:

0-(x^2+14x-392)=0

We add all the numbers together, and all the variables

-(x^2+14x-392)=0

We get rid of parentheses

-x^2-14x+392=0

We add all the numbers together, and all the variables

-1x^2-14x+392=0

a = -1; b = -14; c = +392;
Δ = b2-4ac
Δ = -142-4·(-1)·392
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-42}{2*-1}=\frac{-28}{-2}
=+14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+42}{2*-1}=\frac{56}{-2}
=-28
$